AP EAMCET · Chemistry · Solutions
At \(\mathrm{T}(\mathrm{K})\), the vapour pressure of pure benzene and toluene are 75 and 22 mm Hg respectively. 23.4 g of benzene and 64.4 g of toluene are mixed to form an ideal solution. If the vapours are in equilibrium with the liquid mixture, the mole fraction of toluene in vapour phase is (At.wt of \(\mathrm{C}=12 ; \mathrm{H}=1\) )
- A \(0.406\)
- B \(0.594\)
- C \(0.539\)
- D \(0.461\)
Answer & Solution
Correct Answer
(A) \(0.406\)
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