AP EAMCET · Maths · Hyperbola
If \((1,2)\) is the focus, \(x+2 y=0\) is the directrix and \(\sqrt{2}\) is the eccentricity of a hyperbola, then the equation of the hyperbola is
- A \(x^2-y^2=a^2\)
- B \(3 x^2-8 x y-3 y^2-10 x-20 y+25=0\)
- C \(x y=c^2\)
- D \(3 x^2-8 x y-3 y^2+10 x-20 y-25=0\)
Answer & Solution
Correct Answer
(B) \(3 x^2-8 x y-3 y^2-10 x-20 y+25=0\)
Step-by-step Solution
Detailed explanation
Focus is \((1,2)\), directrix is \(x+2 y=0, e=\sqrt{2}\) \(\therefore\) Hyperbola is…
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