AP EAMCET · Maths · Quadratic Equation
After the roots of the equation \(6 x^3+7 x^2-4 x-2=0\) are diminished by \(h\), if the transformed equation does not contain \(x\) term, then the product of all the possible values of \(h\) is
- A \(1 / 3\)
- B \(-2 / 3\)
- C \(-2 / 9\)
- D \(7 / 3\)
Answer & Solution
Correct Answer
(C) \(-2 / 9\)
Step-by-step Solution
Detailed explanation
The transformed equation's \(x\) term coefficient is \(3(6)h^2 + 2(7)h - 4 = 0\). \(18h^2 + 14h - 4 = 0\) \(9h^2 + 7h - 2 = 0\) Product of the values of \(h = \frac{-2}{9}\)
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