AP EAMCET · Chemistry · Structure of Atom
The wavelength of the electron in the ground state of hydrogen atom is y \(Å\). What is the wavelength of the electron in the fourth orbit of \(\mathrm{He}^{+}\)ion (in \(Å\) ) is
- A \(2 \mathrm{y}\)
- B \(3 y\)
- C \(\mathrm{y}\)
- D \(\frac{3 \mathrm{y}}{2}\)
Answer & Solution
Correct Answer
(D) \(\frac{3 \mathrm{y}}{2}\)
Step-by-step Solution
Detailed explanation
The wavelength of an electron in the nth energy level of a hydrogen-like atom (an atom with only one electron) is given by: \[ \lambda=h / p \] where \(h\) is Planck's constant and \(p\) is the momentum of the electron. The momentum of the electron is related to its energy and…
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