AP EAMCET · Maths · Binomial Theorem
If \({ }^{n-3} C_r+B^{n-3} C_{r-1}+B^{\prime n-3} C_{r-2}+{ }^{n-3} C_{r-3}\) \(={ }^n C_r\) holds. for all \(n \geq r \geq 3\), then \(\left(B \cdot B^{\prime}\right)=\).
- A \((1,5)\)
- B \((5,1)\)
- C \((3,3)\)
- D \((4,2)\)
Answer & Solution
Correct Answer
(C) \((3,3)\)
Step-by-step Solution
Detailed explanation
\({ }^{n-3} C_r+B^{n-3} C_{r-1}+B^{\prime n-3} C_{r-2}\) \(+{ }^{n-3} C_{r-3}={ }^n C_r\) \(\Rightarrow\left({ }^{n-3} C_r+{ }^{n-3} C_{r-1}\right)+\left({ }^{n-3} C_{r-1}+{ }^{n-3} C_{r-2}\right)\) \(+\left({ }^{n-3} C_{r-2}+{ }^{n-3} C_{r-3}\right)\)…
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