AP EAMCET · Maths · Probability
Two persons \(A\) and \(B\) are throwing an unbiased six faced dice alternatively, with the condition that the person who throws 3 first wins the game. If \(A\) starts the game, then probabilities of \(A\) and \(B\) to win the same are, respectively
- A \(\frac{6}{11}, \frac{5}{11}\)
- B \(\frac{5}{11}, \frac{6}{11}\)
- C \(\frac{8}{11}, \frac{3}{11}\)
- D \(\frac{3}{11}, \frac{8}{11}\)
Answer & Solution
Correct Answer
(C) \(\frac{8}{11}, \frac{3}{11}\)
Step-by-step Solution
Detailed explanation
Here, probability of success, \(p=\frac{1}{6}\) and probability of failure. \(q=\frac{5}{6}\) Let \(A\) starts the game, then…
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