AP EAMCET · Maths · Three Dimensional Geometry
\(\triangle \mathrm{ABC}\) is formed by \(\mathrm{A}(1,8,4), \mathrm{B}(0,-11,4)\) and \(C(2,-3,1)\). If \(D\) is the foot of the perpendicular drawn from \(\mathrm{A}\) to \(\mathrm{BC}\), then the coordinates of \(\mathrm{D}\) are
- A \((-4,5,2)\)
- B \((4,-5,2)\)
- C \((4,-5,-2)\)
- D \((4,5,-2)\)
Answer & Solution
Correct Answer
(D) \((4,5,-2)\)
Step-by-step Solution
Detailed explanation
Let \(\mathrm{D}(h, k, l)\) be foot of Perpendicular \(\mathrm{AD}\) on \(\mathrm{BC}\). Equation of line \(\mathrm{BC}\) is \[ \frac{x-2}{2}=\frac{y+3}{8}=\frac{z-1}{-3}=\lambda \text { (say) } \] Since equation passes through \(\mathrm{D}(h, k, l)\) Hence…
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