AP EAMCET · PHYSICS · Magnetic Effects of Current
Two short magnets \(A B\) and \(C D\) are in the \(X-Y\) plane and are parallel to \(X\)-axis and co-ordinates of their centres respectively are \((0,2)\) and \((2,0)\). Line joining the north-south poles of \(C D\) is opposite to that of \(A B\) and lies along the positive \(X\)-axis. The resultant field induction due to \(A B\) and \(C D\) at a point \(P(2,2)\) is \(100 \times 10^{-7} \mathrm{~T}\). When the poles of the magnet \(C D\) are reversed, the resultant field induction is \(50 \times 10^{-7} \mathrm{~T}\). The value of magnetic moments of \(A B\) and \(C D\) (in \(\mathrm{Am}^2\) ) are :
- A \(300 ; 200\)
- B \(600 ; 400\)
- C \(200 ; 100\)
- D \(300 ; 150\)
Answer & Solution
Correct Answer
(A) \(300 ; 200\)
Step-by-step Solution
Detailed explanation
As shown in figure, \(B=B_1+B_2=\frac{\mu_0}{4 \pi}\left(\frac{2 M_1}{r_1^3}+\frac{M_2}{r_2^3}\right)\) \(100 \times 10^{-7}=10^{-7}\left(\frac{2 M_1}{8}+\frac{M_2}{8}\right)\) \(\Rightarrow \quad 2 M_1+M_2=800\) \(\ldots\) (i) If the poles of the magnet \(C D\) are reversed,…
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