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AP EAMCET · PHYSICS · Laws of Motion

Two masses M1 and M2 are arranged as shown in the figure. Let 'a' be the magnitude of the acceleration of the mass M1. If the mass of M1 is doubled and that of M2 is halved, then the acceleration of the system is
(Treat all surfaces as smooth : masses of pulley and rope are negligible )

  1. A M1+M24M1+M2a
  2. B 2M1+M24M1+M2a
  3. C M1+2M24M1+2M2a
  4. D M1+2M2M1+M2a
Verified Solution

Answer & Solution

Correct Answer

(A) M1+M24M1+M2a

Step-by-step Solution

Detailed explanation

Free body diagrams of M1 and M2 are shown below.From the free body diagram of M2M2gsinθ-T=M2aAnd from the free body diagram of M1T=M1aTherefore,a=M2gsinθM1+M2When mass of M1 is doubled and mass of M2 is halved,a'=M22gsinθ2M1+M22⇒a'=M2gsinθ4M1+M2=M1+M24M1+M2a
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