AP EAMCET · Maths · Hyperbola
The equation of the pair of asymptotes of the hyperbola \(\frac{(x-3)^2}{3}-\frac{(y-2)^2}{2}=1\) is
- A \(2 x^2-3 y^2-12 x+12 y-6=0\)
- B \(2 x^2-3 y^2-12 x+12 y+8=0\)
- C \(2 x^2-3 y^2-12 x+12 y-8=0\)
- D \(2 x^2-3 y^2-12 x+12 y+6=0\)
Answer & Solution
Correct Answer
(D) \(2 x^2-3 y^2-12 x+12 y+6=0\)
Step-by-step Solution
Detailed explanation
Equation of hyperbola is \[ \begin{aligned} & \frac{(x-3)^2}{3}-\frac{(y-2)^2}{2}=1 \\ & \Rightarrow 2\left(x^2+9-6 x\right)-3\left(y^2+4-4 y\right)=6 \\ & \Rightarrow 2 x^2-3 y^2-12 x+12 y+6=6 \\ & \Rightarrow 2 x^2-3 y^2-12 x+12 y=0 \end{aligned} \] Pair of asymptotes of the…
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