AP EAMCET · Maths · Circle
If the pair of tangents drawn to the circle \(x^2+y^2=a^2\) from the point \((10,4)\) are perpendicular, then \(a=\)
- A \(\sqrt{58}\)
- B 58
- C \(2 \sqrt{63}\)
- D \(2 \sqrt{45}\)
Answer & Solution
Correct Answer
(A) \(\sqrt{58}\)
Step-by-step Solution
Detailed explanation
Since the tangents are mutually perpendicular \(\therefore \frac{\angle P}{2}=45^{\circ}\) Let the point of contact of the tangent and the circle be \(A\) and \(B\). Then in \(\triangle P A C, P A=C A\) since the triangles are isoscles right angled triangle.…
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