AP EAMCET · Maths · Circle
If the length of the tangent from \((f, g)\) to the circle \(x^2+y^2=6\) be twice the length of the tangent from the same point to the circle \(x^2+y^2+3 x+3 y=0\), then \(f^2+g^2+4 f+4 g+2\) is equal to
- A –1
- B 1
- C 0
- D –2
Answer & Solution
Correct Answer
(C) 0
Step-by-step Solution
Detailed explanation
\[ \begin{aligned} & \text { Given, } P=(f, g) \\ & S: x^2+y^2-6=0 \\ & S^{\prime}: x^2+y^2+3 x+3 y=0 \end{aligned} \] According to the question, \[ \sqrt{S_{11}}=2 \sqrt{S_{11}^{\prime}} \] Squaring on both sides…
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