AP EAMCET · Maths · Differentiation
If \(\sqrt{\frac{y}{x}}+\sqrt{\frac{x}{y}}=2\), then \(\frac{d y}{d x}\) is equal to
- A \(\frac{x^2+y^2}{x+y}\)
- B \(\frac{x^2-y^2}{x+y}\)
- C \(1\)
- D \(2\)
Answer & Solution
Correct Answer
(C) \(1\)
Step-by-step Solution
Detailed explanation
We have \(\sqrt{\frac{y}{x}}+\sqrt{\frac{x}{y}}=2\) \[ \Rightarrow \quad y+x=2 \sqrt{x} \cdot \sqrt{y} \] On squaring both sides, we get…
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