AP EAMCET · Maths · Permutation Combination
A person invites 8 guests to a dinner and places 5 of them at one table and the remaining 3 at another, both the tables being round. The number of ways in which the guests can be arranged is
- A 40320
- B 2688
- C 8064
- D 13440
Answer & Solution
Correct Answer
(B) 2688
Step-by-step Solution
Detailed explanation
The number of ways to select 5 person out of 8 is \({ }^8 C_5\). Now, number of ways to place 5 on round table is 4 ! and number of ways to place 3 on round table is 2 !. So, required number of ways \(={ }^8 C_5 \times 4 ! \times 2 !\)…
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