AP EAMCET · Maths · Probability
A six-faced unbiased die is thrown twice and the sum of the numbers appearing on the upper face is observed to be 7 . The probability that the number 3 has appeared atleast once, is
- A \(\frac{1}{5}\)
- B \(\frac{2}{5}\)
- C \(\frac{3}{5}\)
- D \(\frac{4}{5}\)
Answer & Solution
Correct Answer
(C) \(\frac{3}{5}\)
Step-by-step Solution
Detailed explanation
Sum of the dice is 7 . \[ \begin{aligned} & S=-\{(1,6),(6,1),(2,5),(5,2),(3,4),(4,3)\} \\ & \therefore n(S)=6 \end{aligned} \] Let, \(E=\) Event of getting atleast three 3 or a die \[ \therefore n(E)=2 \]…
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