AP EAMCET · Maths · Circle
If \(\mathrm{P}(2,3)\) and \(\mathrm{Q}(-1,2)\) are conjugate points with respect to the circle \(x^2+y^2+2 g x+3 y-2=0\), then the radius of the circle is
- A \(\frac{19}{6}\)
- B \(\frac{3 \sqrt{21}}{\sqrt{2}}\)
- C \(\frac{3 \sqrt{3}}{\sqrt{2}}\)
- D \(\frac{35}{2}\)
Answer & Solution
Correct Answer
(B) \(\frac{3 \sqrt{21}}{\sqrt{2}}\)
Step-by-step Solution
Detailed explanation
Since \(P(2,3)\) and \(Q(-1,2)\) are conjugate point w.r.t. the circle \(x^2+y^2+2 g x+3 y-2=0\) Hence both the points lie on the polar of the other point Let \(P\left(x_1, y_1\right)=P(2,3)\) \[ Q\left(x_2, y_2\right)=Q(-1,2) \] Hence…
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