AP EAMCET · Maths · Straight Lines
\(A\) is the point of intersection of the lines \(3 x+y-4=0\) and \(x-y=0\). If a line having negative slope makes an angle of \(45^{\circ}\) with the line \(x-3 y+5=0\) and passes through A then its equation is
- A \(x+y=2\)
- B \(x+2 y=3\)
- C \(4 x+3 y=7\)
- D \(x+3 y=4\)
Answer & Solution
Correct Answer
(B) \(x+2 y=3\)
Step-by-step Solution
Detailed explanation
Since, intersection point of the lines \(3 x+y-4=0\) \(x-y=0\) is \(\mathrm{A}(1,1)\) Now, slope of line \(x-3 y+5=0\) is \(\frac{1}{3}\) and slope of required line (m)…
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