AP EAMCET · Maths · Inverse Trigonometric Functions
If the equation \(2 \operatorname{Cot}^{-1}\left(x^2+2 x+k\right)=\pi-3 \operatorname{Tan}^{-1}\left(x^2+2 x+k\right)\) has two distinct real solutions, then all the values of k lie in the interval
- A \((-1,2)\)
- B \((1, \infty)\)
- C \((-\infty, \infty)\)
- D \((-\infty, 1)\)
Answer & Solution
Correct Answer
(D) \((-\infty, 1)\)
Step-by-step Solution
Detailed explanation
Let \(y = x^2+2x+k\). The equation becomes \(2 \operatorname{Cot}^{-1}(y) = \pi - 3 \operatorname{Tan}^{-1}(y)\). Using \(\operatorname{Cot}^{-1}(y) = \frac{\pi}{2} - \operatorname{Tan}^{-1}(y)\):…
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