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AP EAMCET · Maths · Inverse Trigonometric Functions

If the equation \(2 \operatorname{Cot}^{-1}\left(x^2+2 x+k\right)=\pi-3 \operatorname{Tan}^{-1}\left(x^2+2 x+k\right)\) has two distinct real solutions, then all the values of k lie in the interval

  1. A \((-1,2)\)
  2. B \((1, \infty)\)
  3. C \((-\infty, \infty)\)
  4. D \((-\infty, 1)\)
Verified Solution

Answer & Solution

Correct Answer

(D) \((-\infty, 1)\)

Step-by-step Solution

Detailed explanation

Let \(y = x^2+2x+k\). The equation becomes \(2 \operatorname{Cot}^{-1}(y) = \pi - 3 \operatorname{Tan}^{-1}(y)\). Using \(\operatorname{Cot}^{-1}(y) = \frac{\pi}{2} - \operatorname{Tan}^{-1}(y)\):…