AP EAMCET · Maths · Quadratic Equation
If the quadratic equation \(4^{\sec ^2 \alpha} \cdot x^2+2 x+\left(\beta^2-\beta+\frac{1}{2}\right)=0\) has real roots, then the value of \(\cos ^2 \alpha+\cos ^{-1} \beta\) is
- A \(\frac{\pi}{3}\)
- B \(\frac{\pi}{3}+1\)
- C \(\frac{\pi}{2}\)
- D \(\frac{\pi}{2}-1\)
Answer & Solution
Correct Answer
(B) \(\frac{\pi}{3}+1\)
Step-by-step Solution
Detailed explanation
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