AP EAMCET · Maths · Probability
A fair coin is tossed 100 times. The probability of getting tails an odd number of times is
- A \(\frac{1}{2}\)
- B \(\frac{1}{4}\)
- C \(\frac{1}{8}\)
- D \(\frac{3}{8}\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{2}\)
Step-by-step Solution
Detailed explanation
Probability of getting a tail in a single toss \(p=\frac{1}{2}\) and not getting tail, \(q=\frac{1}{2}\). Using Binomial distribution, \(\therefore\) Required probability…
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