AP EAMCET · Chemistry · Chemical Kinetics
Isomerisation of gaseous cyclobutene to butadiene is a first order reaction. At \(\mathrm{T}(\mathrm{K})\), the rate constant of the reaction is \(3.3 \times 10^{-4} \mathrm{~s}^{-1}\). What is the time required (in min ) to complete \(90 \%\) of this reaction at the same temperature? \((\log 2=0.3)\)
- A 116.67
- B 233.34
- C 58.34
- D 350
Answer & Solution
Correct Answer
(A) 116.67
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { } \mathrm{K}=3.3 \times 10^{-4} \mathrm{~s}^{-1} \\ & \mathrm{~K}=\frac{2.303}{\mathrm{t}} \log \frac{\mathrm{a}}{\mathrm{a}-\mathrm{x}} \\ & \therefore \mathrm{k}=\frac{2.303}{\mathrm{t}} \log \frac{100}{10} \\ & \mathrm{t}=\frac{2.303}{3.3 \times…
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