AP EAMCET · Maths · Straight Lines
The circumcentre of the triangle with vertices at \((-2,3),(1,-2)\) and \((2,1)\) is
- A \(\left(\frac{6}{7}, \frac{2}{7}\right)\)
- B \(\left(-\frac{6}{7}, \frac{2}{7}\right)\)
- C \(\left(\frac{6}{7},-\frac{2}{7}\right)\)
- D \(\left(-\frac{6}{7},-\frac{2}{7}\right)\)
Answer & Solution
Correct Answer
(B) \(\left(-\frac{6}{7}, \frac{2}{7}\right)\)
Step-by-step Solution
Detailed explanation
Let vertices of \(\triangle A B C\) is \(A(-2,3), B(1,-2)\) and \(C(2,1)\) \(\therefore\) Circumcentre of triangle is a point where perpendicular bisector of sides meet. So, \(D E\) is perpendicular bisector of \(B C\). So, \(D E\) is perpendicular bisector of \(B C\). \(D\) is…
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