AP EAMCET · Maths · Probability
A Box \(B_1\) contains 3 blue balls and 6 red balls. Another Box \(B_2\) contains 8 blue balls and ' \(n\) ' red balls \((n \in N)\). A ball selected at random from a box is found to be red. If \(p\) is the probability that this red ball drawn is from box \(B_2\), then
- A \(\frac{1}{7} \leq p < \frac{3}{5}\)
- B \(\frac{3}{5} \leq p < 1\)
- C \(0 < p \leq \frac{3}{5}\)
- D \(0 \leq p \leq \frac{1}{7}\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{7} \leq p < \frac{3}{5}\)
Step-by-step Solution
Detailed explanation
According to given information, the required \(\text {probability }=\frac{\frac{1}{2} \times \frac{n}{n+8}}{\left(\frac{1}{2} \times \frac{n}{n+8}\right)+\left(\frac{1}{2} \times \frac{6}{3+6}\right)}\) (According to Baye's theorem)…
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