AP EAMCET · Maths · Hyperbola
The vertices of the hyperbola \(7 x^2-49 y^2=343\) having eccentricity ' \(4 / 3^{\prime}\) is
- A \((0,0)\)
- B \(( \pm 3,0)\)
- C \((0, \pm 5)\)
- D \(( \pm 7,0)\)
Answer & Solution
Correct Answer
(D) \(( \pm 7,0)\)
Step-by-step Solution
Detailed explanation
Equation of given hyperbola is \[ 7 x^2-49 y^2=343 \Rightarrow \frac{x^2}{49}-\frac{y^2}{7}=1 \] So, the coordinate of vertices are \(( \pm 7,0)\). Hence, option (4) is correct.
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