AP EAMCET · Maths · Probability
A bag contains 5 balls of unknown colours. There are equal chances that out of these five balls, there may be 0 or 1 or 2 or 3 or 4 or 5 red balls. A ball is taken out from the bag at random and is found to be red. The probability that it is the only red ball in the bag is
- A \(\frac{1}{5}\)
- B \(\frac{1}{6}\)
- C \(\frac{1}{15}\)
- D \(\frac{1}{30}\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{15}\)
Step-by-step Solution
Detailed explanation
\(P(\text{1 red ball}|\text{red ball drawn}) = \frac{P(\text{red ball drawn}|\text{1 red ball}) P(\text{1 red ball})}{\sum_{k=0}^{5} P(\text{red ball drawn}|k\text{ red balls}) P(k\text{ red balls})}\)…
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