AP EAMCET · Chemistry · p Block Elements (Group 15, 16, 17 & 18)
White phosphorus reacts with sulphuryl chloride to form \(\mathrm{PCl}_5\) and \(X\). Chlorine reacts with \(X\) in the presence of wood charcoal to form \(Y . X\) and \(Y\) are respectively
- A \(\mathrm{SO}_2, \mathrm{SO}_2 \mathrm{Cl}_2\)
- B \(\mathrm{SO}_2, \mathrm{SCl}_4\)
- C \(\mathrm{SO}_3, \mathrm{SO}_2 \mathrm{Cl}_2\)
- D \(\mathrm{SO}_3, \mathrm{SCl}_4\)
Answer & Solution
Correct Answer
(A) \(\mathrm{SO}_2, \mathrm{SO}_2 \mathrm{Cl}_2\)
Step-by-step Solution
Detailed explanation
White phosphorus reacts with sulphuryl chloride to form \(\mathrm{PCl}_5\) and \(\mathrm{SO}_2(X)\). Chlorine reacts with \(\mathrm{SO}_2\) in presence of wood charcoal to form \(\mathrm{SO}_2 \mathrm{Cl}_2(Y)\). The reaction can be written as:…
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