AP EAMCET · Maths · Three Dimensional Geometry
\(\triangle A B C\) is formed by \(A(1,8,4), B(0,-11,4)\) and \(C(2,-3,1)\). If \(D\) is the foot of the perpendicular from \(A\) to \(B C\). Then the coordinates of \(D\) are
- A (– 4, 5, 2)
- B (4, 5, – 2)
- C (4, – 5, 2)
- D (4, – 5, – 2)
Answer & Solution
Correct Answer
(B) (4, 5, – 2)
Step-by-step Solution
Detailed explanation
The vertices of \(\triangle A B C\) are given as \(A(1,8,4)\), \(B(0,-11,4)\) and \(C(2,-3,1)\). Equation of line \(B C\), \[ \frac{x}{2}=\frac{y+11}{8}=\frac{z-4}{-3}=\lambda \text { (say) } \] As point \(D\) is on line \(B C\), so coordinates of \(D\) are…
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