AP EAMCET · Maths · Probability
A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. Then, the probability that none of the balls drawn is blue is
- A \(10 / 21\)
- B \(11 / 21\)
- C \(2 / 7\)
- D \(5 / 7\)
Answer & Solution
Correct Answer
(A) \(10 / 21\)
Step-by-step Solution
Detailed explanation
Given bag contains 2 red, 3 green 2 blue balls…
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