AP EAMCET · Maths · Trigonometric Equations
In \(\triangle \mathrm{ABC}\), if \(\cos \mathrm{A} \cdot \cos \mathrm{B} \cdot \cos \mathrm{C}=\frac{1}{5}\), then \(\tan \mathrm{A} \tan \mathrm{B}+\) \(\tan \mathrm{B} \tan \mathrm{C}+\tan \mathrm{C} \tan \mathrm{A}=\)
- A 4
- B \(\frac{11}{5}\)
- C 6
- D \(\frac{6}{5}\)
Answer & Solution
Correct Answer
(C) 6
Step-by-step Solution
Detailed explanation
Given :- \(\cos A \cdot \cos B \cdot \cos C=\frac{1}{5}\) \(\because \quad A+B+C=\pi \Rightarrow A+B=\pi-C\)…
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