AP EAMCET · Maths · Circle
\(2 x-3 y+1=0\) and \(4 x-5 y-1=0\) are the equations of two diameters of the circle \(S \equiv x^2+y^2+2 g x+2 f y-11=0\). Q and R are the points of contact of the tangents drawn from the point \(P(-2,-2)\) to this circle. If C is the centre of the circle \(S=0\), then the area (in square units) of the quadrilateral \(P Q C R\) is
- A 25
- B 30
- C 24
- D \(36^{\circ}\)
Answer & Solution
Correct Answer
(B) 30
Step-by-step Solution
Detailed explanation
Equation fo diameters of the circle are \(\begin{aligned} & 2 x-3 y+1=0 ...(i)\\ & 4 x-5 y-1=0 ...(ii) \end{aligned}\) On solving equation (i) and (ii) we get centre if circle \(\mathrm{S}=(-g,-f)=(3,4) \Rightarrow g=-3\) and \(f=-4\) Radius of circle's,…
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