AP EAMCET · Maths · Definite Integration
\(\int_{-1}^1 \frac{|x|}{x} d x\) is equal to
- A 1
- B -1
- C 0
- D \(\frac{1}{2}\)
Answer & Solution
Correct Answer
(C) 0
Step-by-step Solution
Detailed explanation
\begin{aligned} \text { } \int_{-1}^1 \frac{|x|}{x} d x & =1 \\ f(x) & =\frac{|x|}{x}=\left\{\begin{array}{cc} -\frac{x}{x}, & x 0 \end{array}=\left\{\begin{array}{cc} -1, & x 0 \end{array}\right.\right. \\ \therefore \quad I & =\int_{-1}^0(-1) d x+\int_0^1(1) d x \\ &…
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