AP EAMCET · Maths · Binomial Theorem
If the sum of all the coefficients of \(\left(\alpha x^2-2 x+1\right)^{2019}\) is equal to the sum of all the coefficients of \((x-\alpha y)^{2019}\), then \(\alpha=\)
- A -1
- B 0
- C 1
- D 2
Answer & Solution
Correct Answer
(C) 1
Step-by-step Solution
Detailed explanation
The sum of the coefficient of \(\left(\alpha x^2-2 x+1\right)^{2019}\) is \((\alpha-1)^{2019}\). (On putting \(\chi=1\) ) and similarly the sum of the coefficients of \((x-\alpha y)^{2019}\) is \((1-\alpha)^{2019}\) (on putting \(x=y=1\) ) Now according to the question,…
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