AP EAMCET · Maths · Pair of Lines
If the equation \(2 x^2+k x y-6 y^2+3 x+y+1=0\), \((k>0)\) represents a pair of straight lines, then their point of intersection is
- A \(\left(\frac{5}{8}, \frac{1}{8}\right)\)
- B \(\left(\frac{5}{8}, \frac{-1}{8}\right)\)
- C \(\left(\frac{-5}{8}, \frac{-1}{8}\right)\)
- D \(\left(\frac{-5}{8}, \frac{1}{8}\right)\)
Answer & Solution
Correct Answer
(C) \(\left(\frac{-5}{8}, \frac{-1}{8}\right)\)
Step-by-step Solution
Detailed explanation
Given equation, \(2 x^2+k x y-6 y^2+3 x+y+1=0\) is a pair of straight line. \(\therefore \quad\left|\begin{array}{ccc}2 & k / 2 & 3 / 2 \\ k / 2 & -6 & 1 / 2 \\ 3 / 2 & 1 / 2 & 1\end{array}\right|=0\)…
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