AP EAMCET · Chemistry · Ionic Equilibrium
When \(200 \mathrm{~mL}\) solution of \(\mathrm{HCl}\) of \(\mathrm{pH}=2\) is mixed with \(300 \mathrm{~mL}\) solution of \(\mathrm{NaOH}\) of \(\mathrm{pH}=12\), the \(\mathrm{pH}\) of resulting solution is \((\log 2=0.3)\)
- A \(2.7\)
- B \(11.3\)
- C \(12\)
- D \(8\)
Answer & Solution
Correct Answer
(B) \(11.3\)
Step-by-step Solution
Detailed explanation
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