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AP EAMCET · Chemistry · Structure of Atom

The wavelength of a microscopic particle of mass \(9.1 \times 10^{-31} \mathrm{~kg}\) is \(182 \mathrm{~nm}\), its kinetic energy in \(\mathrm{J}\) is \(\left(h=6.625 \times 10^{-34} \mathrm{~J} \mathrm{~s}\right)\)

  1. A \(728 \times 10^{-23}\)
  2. B \(7.28 \times 10^{-24}\)
  3. C \(3.64 \times 10^{23}\)
  4. D \(3.64 \times 10^{24}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(7.28 \times 10^{-24}\)

Step-by-step Solution

Detailed explanation

Given, mass of particles \(=9.1 \times 10^{-31} \mathrm{~kg}\) Wavelength \((\lambda)=182 \mathrm{~nm}=182 \times 10^{-9} \mathrm{~m}\) According to de-Broglie equation,…