AP EAMCET · Maths · Parabola
If \(\left(x_1, y_1\right)\) and \(\left(x_2, y_2\right)\) are the points on the parabola \(y^2=32 x\) each at a focal distance of 10 units, then \(2\left(x_1^2+x_2^2+y_1^2+y_2^2\right)=\)
- A \(68\)
- B \(136\)
- C \(272\)
- D \(8\)
Answer & Solution
Correct Answer
(C) \(272\)
Step-by-step Solution
Detailed explanation
\(y^2=32x \implies 4a=32 \implies a=8\) \(\text{Focal distance} = x+a\) \(10 = x+8 \implies x=2\) \(x_1=2, x_2=2\) \(y_1^2=32x_1=32(2)=64\) \(y_2^2=32x_2=32(2)=64\) \(2\left(x_1^2+x_2^2+y_1^2+y_2^2\right) = 2\left(2^2+2^2+64+64\right)\) \(= 2\left(4+4+64+64\right)\)…
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