AP EAMCET · Maths · Limits
If \(\alpha, \beta\) are the roots of the equation \(a x^2+b x+c=0\), then \(\lim _{x \rightarrow \alpha} \frac{1-\cos \left(a x^2+b x+c\right)}{(x-\alpha)^2}=\)
- A \(a^2(\alpha-\beta)^2\)
- B \(4 a^2(\alpha-\beta)^2\)
- C \(\frac{a^2}{2}(\alpha-\beta)^2\)
- D \(2 a^2(\alpha-\beta)^2\)
Answer & Solution
Correct Answer
(C) \(\frac{a^2}{2}(\alpha-\beta)^2\)
Step-by-step Solution
Detailed explanation
\(\lim _{x \rightarrow \alpha} \frac{1-\cos \left(a x^2+b x+c\right)}{(x-\alpha)^2} = \lim _{x \rightarrow \alpha} \frac{1-\cos \left(a(x-\alpha)(x-\beta)\right)}{(x-\alpha)^2}\)…
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