AP EAMCET · Chemistry · Chemical Bonding and Molecular Structure

The hybridization of $Se$ in ${SeF}_{4}$ and its geometry respectively are

A ${sp}^{3} d$ , see-saw shaped
B $s p^{3} d^{2}$ , octahedral
C $s p^{3} d^{3}$ , trigonal planar
D $s p^{3} d^{2}$ , square planar

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Answer & Solution

Correct Answer

(A) ${sp}^{3} d$ , see-saw shaped

Step-by-step Solution

Detailed explanation

Selenium has the six unpaired electron in outermost shell for bonding. After that four electrons formed the bonding with the fluorine atoms and one lone pair present on the selenium. It has the see-saw shape geometry because on the repulsion due to lone pair. It has the four…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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$- OH$	$- CN$	$- {CO}_{2} H$	$- {OCH}_{3}$	$- {NHCOCH}_{3}$	$- CHO$
I	II	III	IV	V	VI

The hybridization of Se in SeF4 and its geometry respectively are

Step-by-step Solution

The hybridization of $Se$ in ${SeF}_{4}$ and its geometry respectively are