AP EAMCET · Maths · Differentiation
If \(y=\sqrt{\frac{1+\tan x}{1-\tan x}}\), then \(\frac{d y}{d x}=\)
- A \(\frac{1}{2}\left(\sqrt{\frac{1-\tan x}{1+\tan x}}\right) \sec ^2\left(\frac{\pi}{4}+x\right)\)
- B \(\frac{1}{2}\left(\sqrt{\frac{1-\tan x}{1+\tan x}}\right) \sec \left(\frac{\pi}{4}+x\right)\)
- C \(\left(\sqrt{\frac{1-\tan x}{1+\tan x}}\right) \sec ^2\left(\frac{\pi}{4}+x\right)\)
- D \(\frac{1}{2}\left(\sqrt{\frac{1+\tan x}{1-\tan x}}\right) \sec ^2\left(\frac{\pi}{4}+x\right)\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{2}\left(\sqrt{\frac{1-\tan x}{1+\tan x}}\right) \sec ^2\left(\frac{\pi}{4}+x\right)\)
Step-by-step Solution
Detailed explanation
Given, \(y=\sqrt{\frac{1+\tan x}{1-\tan x}}\)…
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