AP EAMCET · Chemistry · Solid State
The diffraction pattern of crystalline solid gave a peak at \(2 \theta=60^{\circ}\). What is the distance (in cm ) between the layers which gave this peak?
( \(\lambda\) of X-rays is \(1.54 Å)\left(\sin 30^{\circ}=0.5, \sin 60^{\circ}=0.866\right.\); \(n=1\) )
- A \(8.89 \times 10^{-9}\)
- B \(8.89 \times 10^{-1}\)
- C \(1.54 \times 10^{-8}\)
- D \(1.54\)
Answer & Solution
Correct Answer
(C) \(1.54 \times 10^{-8}\)
Step-by-step Solution
Detailed explanation
According to Bragg's law \(\mathrm{n} \lambda=2 \mathrm{~d} \sin \theta\) Given, \(\mathrm{n}=\) order \(=1\)…
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