AP EAMCET · Chemistry · Solutions
\(3.1 \mathrm{~g}\) of a compound, ' \(X\) ' (molar mass \(=62 \mathrm{~g}\) \(\mathrm{mol}^{-1}\) ) is dissolved in \(19.5 \mathrm{~g}\) of other compound, \(Y\) (molar mass \(=78 \mathrm{~g} \mathrm{~mol}^{-1}\) ). The ratio of mole fractions of \(X\) and \(Y\) in the solution is
- A \(1: 5\)
- B \(5: 1\)
- C \(4: 1\)
- D \(1: 4\)
Answer & Solution
Correct Answer
(A) \(1: 5\)
Step-by-step Solution
Detailed explanation
( ) The number of moles of \[ X=\frac{W_X}{M_X}=\frac{3.1 \mathrm{~g}}{62 \mathrm{~g} \mathrm{~mol}^{-1}}=0.05 \mathrm{~mol} \] The number of moles of \[ Y=\frac{W_Y}{M_Y}=\frac{19.5 \mathrm{~g}}{78 \mathrm{~g} \mathrm{~mol}^{-1}}=0.25 \mathrm{~mol} \] Mole fraction of…
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