AP EAMCET · Chemistry · Solutions
The depression in freezing point of solution of molality \(0.01 \mathrm{~mol} \mathrm{~kg}^{-1}\) is highest with respect to which of the solvent? (Whose \(K_f\) is given in brackets)
- A Water (1.86)
- B Benzene (5.12)
- C Carbon tetrachloride (31.8)
- D Cyclohexane (20.0)
Answer & Solution
Correct Answer
(C) Carbon tetrachloride (31.8)
Step-by-step Solution
Detailed explanation
Given, molality of solution \(=0.01 \mathrm{~mol} \mathrm{~kg}^{-1}\) We know that, \(\Delta T_f=i K_f m\)...(i) (where, symbols have their usual meaning) The van't Hoff factor for all given solvent is 1 as they does not ionise. Therefore, For, Eq (i) \(\Delta T_f \propto K_f\)…
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