AP EAMCET · Chemistry · Chemical Bonding and Molecular Structure
The species, which has the bond order same as that of \(\mathrm{F}_2\) molecule is
- A \(\mathrm{O}_2^{+}\)
- B \(\mathrm{O}_2^{2-}\)
- C \(\mathrm{O}_2\)
- D \(\mathrm{N}_2^{+}\)
Answer & Solution
Correct Answer
(B) \(\mathrm{O}_2^{2-}\)
Step-by-step Solution
Detailed explanation
MO for the fluorine molecule, the 14 valence electrons of the fluorine atoms fill 4 bonding and 3 anti-bonding orbital thus bond order is 1 . Bond order \[ =\frac{\text { bonding electrons }- \text { anti }- \text { bonding electrons }}{2} \] In the same way…
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