AP EAMCET · Chemistry · Classification of Elements and Periodicity in Properties
The correct order of bond enthalpy of given molecules is
- A \(\mathrm{O}_2 < \mathrm{N}_2 < \mathrm{H}_2\)
- B \(\mathrm{N}_2 < \mathrm{O}_2 < \mathrm{H}_2\)
- C \(\mathrm{H}_2 < \mathrm{N}_2 < \mathrm{O}_2\)
- D \(\mathrm{H}_2 < \mathrm{O}_2 < \mathrm{N}_2\)
Answer & Solution
Correct Answer
(D) \(\mathrm{H}_2 < \mathrm{O}_2 < \mathrm{N}_2\)
Step-by-step Solution
Detailed explanation
The correct order of bond enthalpy \(=\mathrm{H}_2 < \mathrm{O}_2 < \mathrm{N}_2\) This is due to increasing bond strength due to single, double and triple bonds respectively \((\mathrm{H}-\mathrm{H}, \mathrm{O}=\mathrm{O}, \mathrm{N} \equiv\) N).
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