AP EAMCET · Chemistry · Structure of Atom
Two particles of masses \(m\) and \(2 m\) have equal kinetic energies. The de-Broglie wavelengths are in the ratio of
- A \(1: 1\)
- B \(1: 2\)
- C \(1: \sqrt{2}\)
- D \(\sqrt{2}: 1\)
Answer & Solution
Correct Answer
(D) \(\sqrt{2}: 1\)
Step-by-step Solution
Detailed explanation
As we know \[ \begin{aligned} & \lambda=\frac{h}{m v} \\ & \lambda=\frac{h}{\sqrt{2 m E}} \end{aligned} \] \[ \left[\because E=\frac{1}{2} m v^2\right] \] Since, \(h\) is a constant and kinetic energy is same for both particles, so,…
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