AP EAMCET · Chemistry · Electrochemistry
The conductivity of \(0.001 \mathrm{M}\) acetic acid at a certain temperature is \(5.07 \times 10^{-5} \mathrm{~S} \mathrm{~cm}^{-1}\). If \(\wedge_m^0\) of acetic acid at the same temperature is \(390 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\), the dissociation constant of acetic acid at that temperature is:
- A \(1.94 \times 10^{-5}\)
- B \(1.94 \times 10^{-3}\)
- C \(1.94 \times 10^{-4}\)
- D \(1.94 \times 10^{-6}\)
Answer & Solution
Correct Answer
(A) \(1.94 \times 10^{-5}\)
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