AP EAMCET · Chemistry · Chemical Kinetics
\(R \longrightarrow P\) is a first order reaction. The concentration of \(R\) changed from 0.04 to \(0.03 \mathrm{~mol} \mathrm{~L}^{-1}\) in 40 min. What is the average velocity of the reaction in \(\mathrm{mol} \mathrm{L}^{-1}\) \(\mathrm{s}^{-1} ?\)
- A \(2.5 \times 10^{-4}\)
- B \(4.167 \times 10^{-6}\)
- C \(4.167 \times 10^6\)
- D \(2.5 \times 10^{-5}\)
Answer & Solution
Correct Answer
(B) \(4.167 \times 10^{-6}\)
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