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AP EAMCET · Chemistry · General Organic Chemistry

An organic compound of molecular formula C6H6Br2 has six carbon atoms in a ring system, two non-conjugate double bonds and two bromo groups at 1,4 positions. Then the compound is

  1. A aromatic but non-homo-cyclic
  2. B aromatic and hetero-cyclic
  3. C homo-cyclic but not aromatic
  4. D neither homo-cyclic nor hetero-cyclic
Verified Solution

Answer & Solution

Correct Answer

(C) homo-cyclic but not aromatic

Step-by-step Solution

Detailed explanation

C6H6Br2:- Double bond equivalent formula = C-H2-X2+1 C=6; H=6;X=2 DBU=6-62-22+1=6-4+1=3 So, it has one ring with two double bonds. It has the two bromo groups at the 1,4 position and has the six membered carbon ring with non-conjugated double bond. Hence, the structure of…