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AP EAMCET · Chemistry · Structure of Atom

The difference between the radii of \(3^{\text {rd }}\) and \(2^{\text {nd }}\) orbit of H -atom is \(x\) \(\mathrm{pm}\). The difference between the radii of \(4^{\text {th }}\) and \(3^{\text {rd }}\) orbit of \(\mathrm{Li}^{2+}\) ion is \(y \mathrm{pm}. y: x\) is equal to

  1. A \(15: 7\)
  2. B \(7: 15\)
  3. C \(3: 1\)
  4. D \(1: 3\)
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(B) \(7: 15\)

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