AP EAMCET · Chemistry · Structure of Atom
When a metal surface is exposed to certain frequency of electromagnetic radiation. The kinetic energy of electron ejected from metal surface is \(0.20 \mathrm{eV}\). If its work function \(\left(W_0\right)\) is \(4.80 \mathrm{eV}\), the approximate frequency of radiation falling on the metal surface in \(\mathrm{Hz}\) is
- A \(1.98 \times 10^{15}\)
- B \(1.21 \times 10^{16}\)
- C \(1.21 \times 10^{15}\)
- D \(1.98 \times 10^{16}\)
Answer & Solution
Correct Answer
(C) \(1.21 \times 10^{15}\)
Step-by-step Solution
Detailed explanation
Given, work function \(\left(\omega_0\right)\) i.e. energy for ejection \(=4.80 \mathrm{eV}\) and kinetic energy of the ejected electron. \[ (\mathrm{KE})=0.20 \mathrm{eV} \text {. } \] According to photoelectric current relation. Total energy…
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